What is the load from a 4-kilowatt electric heater operating at 240 volts?

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Multiple Choice

What is the load from a 4-kilowatt electric heater operating at 240 volts?

Explanation:
To determine the load in amps drawn by a 4-kilowatt electric heater operating at 240 volts, we utilize the formula that relates power (P), voltage (V), and current (I): \[ P = V \times I \] Where: - \( P \) is the power in watts (W). - \( V \) is the voltage in volts (V). - \( I \) is the current in amperes (A). First, we convert kilowatts to watts: \[ 4 \text{ kW} = 4,000 \text{ W} \] Next, we rearrange the formula to solve for current (I): \[ I = \frac{P}{V} \] Substituting the known values: \[ I = \frac{4000 \text{ W}}{240 \text{ V}} \] Calculating this gives: \[ I = \frac{4000}{240} \approx 16.67 \text{ A} \] Thus, the correct current draw from a 4-kilowatt heater operating at 240 volts is approximately 16.67 A. The result corresponds to the first choice

To determine the load in amps drawn by a 4-kilowatt electric heater operating at 240 volts, we utilize the formula that relates power (P), voltage (V), and current (I):

[

P = V \times I

]

Where:

  • ( P ) is the power in watts (W).

  • ( V ) is the voltage in volts (V).

  • ( I ) is the current in amperes (A).

First, we convert kilowatts to watts:

[

4 \text{ kW} = 4,000 \text{ W}

]

Next, we rearrange the formula to solve for current (I):

[

I = \frac{P}{V}

]

Substituting the known values:

[

I = \frac{4000 \text{ W}}{240 \text{ V}}

]

Calculating this gives:

[

I = \frac{4000}{240} \approx 16.67 \text{ A}

]

Thus, the correct current draw from a 4-kilowatt heater operating at 240 volts is approximately 16.67 A. The result corresponds to the first choice

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